1
MHT CET 2025 23rd April Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two tuning forks when sounded together produce 4 beats per second. One of the forks is in unison with 23 cm length of sonometer wire and other with 24 cm length of the same wire. The frequencies of the two tuning forks are

A
$96 \mathrm{~Hz}, 92 \mathrm{~Hz}$
B
$92 \mathrm{~Hz}, 88 \mathrm{~Hz}$
C
$72 \mathrm{~Hz}, 68 \mathrm{~Hz}$
D
$48 \mathrm{~Hz}, 44 \mathrm{~Hz}$
2
MHT CET 2025 23rd April Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let the speed of light and the polarising angle for a given medium be ' $V$ ' and ' $i_p$ ' respectively. The relation between them is : ( $\mathrm{C}=$ speed of light in vacuum)

A
$\mathrm{V}=\mathrm{C} \cos \left(\mathrm{i}_{\mathrm{p}}\right)$
B
$V \cos \left(i_p\right)=C \sin \left(i_p\right)$
C
$\mathrm{C}=\mathrm{V} \cot \left(\mathrm{i}_{\mathrm{p}}\right)$
D
$\mathrm{V} \sin \left(\mathrm{i}_{\mathrm{p}}\right)=\mathrm{C} \cos \left(\mathrm{i}_{\mathrm{p}}\right)$
3
MHT CET 2025 23rd April Morning Shift
MCQ (Single Correct Answer)
+1
-0

The equivalent resistance of the following circuit when no current flows in the resistance of $5 \Omega$ is nearly

MHT CET 2025 23rd April Morning Shift Physics - Current Electricity Question 2 English
A
$13 \Omega$
B
$17 \Omega$
C
$19 \Omega$
D
$21 \Omega$
4
MHT CET 2025 23rd April Morning Shift
MCQ (Single Correct Answer)
+1
-0

In the case of common emitter transistor amplifier, the ratio of collector current to emitter current is 0.96 , then the current gain $(\beta)$ of the amplifier is

A
6
B
48
C
24
D
12
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