1
MHT CET 2023 13th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

A vector $$\bar{a}$$ has components 1 and $$2 p$$ with respect to a rectangular Cartesian system. This system is rotated through a certain angle about origin in the counter clock wise sense. If, with respect to the new system, $$\bar{a}$$ has components 1 and $$(p+1)$$, then

A
$$\mathrm{p}=1$$ or $$\mathrm{p}=\frac{1}{3}$$
B
$$\mathrm{p}=-1$$ or $$\mathrm{p}=\frac{-1}{3}$$
C
$$\mathrm{p}=\frac{-1}{3}$$ or $$\mathrm{p}=1$$
D
$$\mathrm{p}=\frac{1}{3}$$ or $$\mathrm{p}=-1$$
2
MHT CET 2023 13th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

A line is drawn through the point $$(1,2)$$ to meet the co-ordinate axes at $$\mathrm{P}$$ and $$\mathrm{Q}$$ such that it forms a $$\triangle \mathrm{OPQ}$$, where $$\mathrm{O}$$ is the origin. If the area of $$\triangle \mathrm{OPQ}$$ is least, then the slope of the line $$\mathrm{PQ}$$ is

A
$$-2$$
B
2
C
$$\frac{-1}{2}$$
D
$$\frac{1}{2}$$
3
MHT CET 2023 13th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If feasible region is as shown in the figure, then related inequalities are

MHT CET 2023 13th May Morning Shift Mathematics - Linear Programming Question 15 English
A
$$3 x+4 y \geq 12,4 x+7 y \leq 28, y \leq 1, x \geq 0, y \geq 0$$
B
$$3 x+4 y \geq 12,4 x+7 y \leq 28, y \geq 1, x \geq 0, y \geq 0$$
C
$$3 x+4 y \leq 12,4 x+7 y \leq 28, y \leq 1, x \geq 0, y \geq 0$$
D
$$3 x+4 y \leq 12,4 x+7 y \geq 28, y \geq 1, x \geq 0, y \geq 0$$
4
MHT CET 2023 13th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The general solution of the equation $$3 \sec ^2 \theta=2 \operatorname{cosec} \theta$$ is

A
$$\mathrm{n} \pi+\frac{\pi}{4}, \mathrm{n} \in \mathrm{Z}$$
B
$$2 \mathrm{n} \pi+(-1)^{\mathrm{n}} \frac{\pi}{12}, \mathrm{n} \in \mathrm{Z}$$
C
$$\mathrm{n} \pi+(-1)^{\mathrm{n}} \frac{\pi}{6}, \mathrm{n} \in \mathrm{Z}$$
D
$$\mathrm{n} \pi+(-1)^{\mathrm{n}} \frac{\pi}{3}, \mathrm{n} \in \mathrm{Z}$$
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