MHT CET 2023 13th May Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2023 13th May Morning Shift

MCQ (Single Correct Answer)

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The parametric equations of the curve $$x^2+y^2+a x+b y=0$$ are

$$x=\frac{\mathrm{a}}{2}+\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \cos \theta, y=\frac{\mathrm{b}}{2}+\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \sin \theta$$

$$x=\frac{\mathrm{a}}{2}-\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \cos \theta, y=\frac{\mathrm{b}}{2}-\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \sin \theta$$

$$x=-\frac{\mathrm{a}}{2}+\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \cos \theta, y=-\frac{\mathrm{b}}{2}+\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \sin \theta$$

$$x=-\frac{\mathrm{a}}{2}-\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \cos \theta, y=-\frac{\mathrm{b}}{2}-\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \sin \theta$$

MHT CET 2023 13th May Morning Shift

MCQ (Single Correct Answer)

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The sides of a triangle are three consecutive natural numbers and its largest angle is twice the smallest one, then the sides of the triangle (in units) are

3, 4, 5

4, 5, 6

5, 6, 7

2, 3, 4

MHT CET 2023 13th May Morning Shift

MCQ (Single Correct Answer)

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$$x, y, z$$ are in G.P. and $$\tan ^{-1} x, \tan ^{-1} y, \tan ^{-1} z$$ are in A.P., then

$$6 x=4 y=3 z$$

$$2 x=3 y=6 z$$

$$6 x=3 y=2 z$$

$$x=y=\mathrm{z}$$

MHT CET 2023 13th May Morning Shift

MCQ (Single Correct Answer)

-0

In $$\triangle A B C$$ with usual notation, $$\frac{\cos A}{a}=\frac{\cos B}{b}=\frac{\cos C}{c}$$ and $$a=\frac{1}{\sqrt{6}}$$, then the area of triangle is _______ sq. units.

$$\frac{1}{8}$$

$$\frac{1}{24 \sqrt{3}}$$

$$\frac{1}{24}$$

$$\frac{1}{8 \sqrt{3}}$$

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