1
GATE EE 2013
MCQ (Single Correct Answer)
+1
-0.3
In the circuit shown below what is the output voltage $$\left( {{V_{out}}} \right)$$ in Volts If a silicon transfer $$Q$$ and an ideal op-amp are used? GATE EE 2013 Analog Electronics - Operational Amplifier Question 58 English
A
$$-15$$
B
$$-0.7$$
C
$$+0.7$$
D
$$+15$$
2
GATE EE 2013
MCQ (Single Correct Answer)
+2
-0.6
In the circuit shown below the op-amps are ideal. Then $${V_{out}}$$ in Volts is GATE EE 2013 Analog Electronics - Operational Amplifier Question 24 English
A
$$4$$
B
$$6$$
C
$$8$$
D
$$10$$
3
GATE EE 2013
MCQ (Single Correct Answer)
+1
-0.3
In the feedback network shown below, if the feedback factor $$k$$ is increased, then the GATE EE 2013 Analog Electronics - Feedback Amplifiers and Oscillator Circuits Question 9 English
A
input impedance increases and output impedance decreases.
B
input impedance increases and output impedance also increases.
C
input impedance decreases and output impedance also decreases.
D
input impedance decreases and output impedance increases.
4
GATE EE 2013
MCQ (Single Correct Answer)
+2
-0.6
The state variable formulation of a system is given as
$$\left[ {\matrix{ {\mathop {{x_1}}\limits^ \bullet } \cr {\mathop {{x_2}}\limits^ \bullet } \cr } } \right] = \left[ {\matrix{ { - 2} & 0 \cr 0 & { - 1} \cr } } \right]\left[ {\matrix{ {{x_1}} \cr {{x_2}} \cr } } \right] + \left[ {\matrix{ 1 \cr 1 \cr } } \right]u,\,\,{x_1}\left( 0 \right) = 0,$$
$${x_2}\left( 0 \right) = 0$$ and $$y = \left[ {\matrix{ 1 & 0 \cr } } \right]\left[ {\matrix{ {{x_1}} \cr {{x_2}} \cr } } \right]$$

The response $$y(t)$$ to a unit step input is

A
$${1 \over 2} - {1 \over 2}{e^{ - 2t}}$$
B
$$1 - {1 \over 2}{e^{ - 2t}} - {1 \over 2}{e^{ - t}}$$
C
$${e^{ - 2t}} - {e^{ - t}}$$
D
$$1 - {e^{ - t}}$$
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