1
GATE EE 2013
MCQ (Single Correct Answer)
+1
-0.3
The transfer function $${{{V_2}\left( s \right)} \over {{V_1}\left( s \right)}}$$ of the circuit shown below is GATE EE 2013 Control Systems - Basics of Control System Question 6 English
A
$${{0.5s + 1} \over {s + 1}}$$
B
$${{3s + 6} \over {s + 2}}$$
C
$${{s + 2} \over {s + 1}}$$
D
$${{s + 1} \over {s + 2}}$$
2
GATE EE 2013
MCQ (Single Correct Answer)
+2
-0.6
The signal flow graph for a system is given below. The transfer function $${{Y\left( s \right)} \over {U\left( s \right)}}$$ for this system is GATE EE 2013 Control Systems - Block Diagram and Signal Flow Graph Question 6 English
A
$${{s + 1} \over {5{s^2} + 6s + 2}}$$
B
$${{s + 1} \over {{s^2} + 6s + 2}}$$
C
$${{s + 1} \over {{s^2} + 4s + 2}}$$
D
$${1 \over {5{s^2} + 6s + 2}}$$
3
GATE EE 2013
MCQ (Single Correct Answer)
+2
-0.6
The open-loop transfer function of a $$dc$$ motor is given as $${{\omega \left( s \right)} \over {{V_a}\left( s \right)}} = {{10} \over {1 + 10s}}.$$ When connected in feedback as shown below, the approximate value of $${K_a}$$ that will reduce the time constant of the closed loop system by one hundred times as compared to that of the open-loop system is GATE EE 2013 Control Systems - Time Response Analysis Question 10 English
A
$$1$$
B
$$5$$
C
$$10$$
D
$$100$$
4
GATE EE 2013
MCQ (Single Correct Answer)
+1
-0.3
The Bode plot of a transfer function $$G(s)$$ is shown in the figure below. GATE EE 2013 Control Systems - Polar Nyquist and Bode Plot Question 36 English

The gain is $$\left( {20\log \left| {G\left( s \right)} \right|} \right)$$ is $$32$$ $$dB$$ and $$–8$$ $$dB$$ at $$1$$ $$rad/s$$ and $$10$$ $$rad/s$$ respectively. The phase is negative for all $$\omega .$$ Then $$G(s)$$ is

A
$${{39.8} \over s}$$
B
$${{39.8} \over {{s^2}}}$$
C
$${{32} \over s}$$
D
$${{32} \over {{s^2}}}$$
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