1
GATE EE 2000
MCQ (More than One Correct Answer)
+1
-0
Triangular $$PWM$$ control, when applied to a $$BJT$$ based three phase voltage source inverter, introduces.
A
low order harmonic voltages on the $$dc$$ side.
B
very high order harmonic voltage on the $$dc$$ side
C
low order harmonic voltage on the $$ac$$ side
D
very high order harmonic voltage on the $$ac$$ side
2
GATE EE 2000
MCQ (Single Correct Answer)
+2
-0.6
A three phase voltage source inverter supplies a purely inductive three phase load. Upon Fourier analysis, the output voltage waveform is found to have an $${h^{th}}$$ order harmonic of magnitude α h times that of the fundamental frequency component $$\left( {{\alpha _h} < 1} \right),$$ the load current would then have an $${h^{th}}$$ order harmonic of magnitude
A
zero
B
$${{\alpha _h}}$$ times the fundamental frequency component
C
$${h{\alpha _h}}$$ times the fundamental frequency component
D
$${\raise0.5ex\hbox{$\scriptstyle {{\alpha _h}}$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle h$}}$$ times the fundamental frequency component
3
GATE EE 2000
Subjective
+5
-0
A single phase voltage source of magnitude $${V_s}$$ and frequency $$\omega \,\,\left( {rad\,/\,\sec } \right)$$ is connected to an inductance $$L$$ through an antiparallel back-to-back pair of thyristors. The forward and reverse conducting thyristors are fired at an angle of $$\alpha \ge \pi /2$$ from the positive going and negative going zer crossings of the supply voltage respectively, in each cycle. Obtain an expression for the inductor current in each cycle for a given value of $$\alpha .$$ The voltage drop across the thyristors, when either of them is in conduction, may be assumed to be negligible.
4
GATE EE 2000
MCQ (Single Correct Answer)
+2
-0.6
The incremental cost characteristic of two generators delivering $$200$$ $$MW$$ are as follows $$\,\,\,{{d{F_1}} \over {d{P_1}}} = 20 + 0.1{P_1},\,\,{{d{F_2}} \over {d{P_2}}} = 16 + 0.2{P_2}$$
For economic operation, the generations $${P_1}$$ and $${P_2}$$ should be
A
$${P_1} = {P_2} = 100\,MW$$
B
$${P_1} = 80MW,\,\,{P_2} = 120\,MW$$
C
$${P_1} = 200MW,\,\,{P_2} = 0\,MW$$
D
$${P_1} = 120MW,\,\,{P_2} = 80\,MW$$
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