1
TS EAMCET 2022 (Online) 19th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

An object of mass 15 kg is attached to the end of a metal wire of unstretched length 1.0 m . The object is then whirled in a vertical circle with an angular velocity of $4 \mathrm{rad} / \mathrm{s}$ at the bottom of the circle. If the cross sectional area of the wire is $0.05 \mathrm{~cm}^2$ and Young's modulus of metal is $2 \times 10^{11} \mathrm{~N} / \mathrm{m}^2$, then the elongation of the wire when the mass is at the lowest point of its path (take, $g=10 \mathrm{~m} / \mathrm{s}^2$ )

A

0.27 mm

B

0.39 mm

C

0.55 mm

D

0.25 mm

2
TS EAMCET 2022 (Online) 18th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

A swimming pool has a depth of 22 m and area $700 \mathrm{~m}^2$. Calculate fractional change $\Delta v / v$ of water at the bottom of the swimming pool, given that the bulk modulus of water is $2.2 \times 10^9 \mathrm{Nm}^{-2}, g=10 \mathrm{~m} / \mathrm{s}^2$, and density of water is $1000 \mathrm{~kg} / \mathrm{m}^3$

A

$22 \times 10^{-4}$

B

$0.7 \times 10^{-4}$

C

$0.31 \times 10^{-4}$

D

$10^{-4}$

3
TS EAMCET 2022 (Online) 18th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { Match the following. } $$

Column-I Column-II
(A) Shear modulus (I) Resistance to change in volume
(B) Shearing stress (II) Proportionality constant
(C) Elastic fatigue (III) Tangential stress
(D) Modulus of elasticity (IV) Temporary loss of elastic property
(v) Resistance to change against deformation force

The correct match is

A
A B C D
II V I III
B
A B C D
V III IV II
C
A B C D
III IV II V
D
A B C D
V II IV I
4
TS EAMCET 2020 (Online) 14th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two metal wires $A$ and $B$ have length $L$ and $3 L$ respectively. The radius of cross-sectional circular area of wire $A$ and $B$ are $R$ and $2 R$, respectively. These wires are joined end to end along their axis. When one end of the combined system is fixed and other end is pulled with a constant force $F$, the elongation in both the wires is equal. If $Y_A$ and $Y_B$ are Young's modulus of wire $A$ and $B$, then the $Y_B / Y_A$ is

A

$\frac{3}{4}$

B

$\frac{4}{3}$

C

$\frac{2}{3}$

D

$\frac{3}{2}$

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