A parallel plate capacitor of capacitance $10 \mu \mathrm{~F}$ is charged by a 220 V supply. The capacitor is then disconnected from the supply and is connected to another uncharged parallel plate capacitor of capacitance $12 \mu \mathrm{~F}$. The loss of electrostatic energy in this process is

If the rate of change of electric field across the plates of a parallel plate capacitor is $E$ and the displacement current is $I$, then the area of one plate of the capacitor is ( $\varepsilon_0$ is permittivity of free space)

A parallel plate capacitor with air as dielectric has a capacitance of $4 \mu \mathrm{~F}$. The space between the plates of the capacitor is completely filled with a material of dielectric constant 5 and charged to a potential of 100 V . The work done to completely remove the dielectric material after the capacitor is disconnected from the battery is

If the rate of change in electric flux between the plates of a capacitor is $9 \pi \times 10^3 \mathrm{Vms}^{-1}$, then the displacement current inside the capacitor is