An alkene $X\left(\mathrm{C}_6 \mathrm{H}_{12}\right)$ on ozonolysis gave acetaldehyde and ethyl methyl ketone. What is the product formed when $X$ reacts with HBr ?

An alkene $X$ with formula $\mathrm{C}_4 \mathrm{H}_8$ does not exhibit geometrical isomerism. In the conversion of $X$ to $Y$, the correct sequence of reagents $A$ and $B$ used are ( $Y$ gives iodoform test)

An alkene $(X)$ on ozonolysis gives propanal and ethanal. What is $X$ ?

Match the following.

The correct answer is