' $X$ ' is the isomer of $\mathrm{C}_6 \mathrm{H}_{14}$. It has four primary carbons and two tertiary carbons, ' $X$ ' can be prepared from which of the following reactions?

$$ \begin{aligned} &\text { What are } X \text { and } Y \text { in the following reaction sequence? }\\ &\mathrm{C}_5 \mathrm{H}_{12} \mathrm{O} \xrightarrow[573 \mathrm{~K}]{\mathrm{Cu}} \mathrm{C}_5 \mathrm{H}_{10} \xrightarrow[\text { (ii) } \mathrm{Zn}+\mathrm{H}_2 \mathrm{O}]{\text { (i) } \mathrm{O}_3} X+Y \end{aligned} $$

$$ \text { Match the following } $$

The correct answer is

Chlorobenzene when subjected to fittig reaction gives a compound ' $X$ '. The sum of $\sigma$ and $\pi$ - bonds in $X$ is