TS EAMCET 2023 (Online) 13th May Evening Shift | Simple Harmonic Motion Question 14 | Physics

A force of 6.4 N stretches a vertical spring by 0.1 m . If it were to oscillate with a period of $\pi / 4$, then the mass that is to be suspended from the spring is

$\frac{\pi}{4} \mathrm{~kg}$

1 kg

$\frac{1}{\pi} \mathrm{~kg}$

10 kg

TS EAMCET 2023 (Online) 13th May Morning Shift

MCQ (Single Correct Answer)

-0

A pendulum has a time period $T$ in air. Whạt it is made to oscillate in water its time period is $\sqrt{2} T$. Then the relative density of the material of the bob of the pendulum is (neglect damping)

$\sqrt{2}$

$2 \sqrt{2}$

TS EAMCET 2023 (Online) 12th May Evening Shift

MCQ (Single Correct Answer)

-0

A clock is designed based on the oscillation of a spring-block system suspended vertically in the absence of air-resistance. Assume it shows the correct time when a spring of stiffness $k$ and block is mass $m$ are used. If the block is replaced by another block of mass $4 m$, choose the correct option

The clock runs slow by 0.5 s for every second

The clock runs fast by 0.5 s for every one second

The clock runs fast by 1 s for every one second

The clock runs slow by 1 s for every one second

TS EAMCET 2023 (Online) 12th May Morning Shift

MCQ (Single Correct Answer)

-0

For a particle executing simple harmonic motion, the kinetic energy of the particle at a distance of 4 cm from the mean position is $1 / 3$ rd of the maximum kinetic energy. The amplitude of the motion is

$2 \sqrt{6} \mathrm{~cm}$

$\frac{2}{\sqrt{6}} \mathrm{~cm}$

$\sqrt{2} \mathrm{~cm}$

$\frac{6}{\sqrt{2}} \mathrm{~cm}$

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