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TS EAMCET 2023 (Online) 12th May Morning Shift
MCQ (Single Correct Answer)
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-0
For a particle executing simple harmonic motion, the kinetic energy of the particle at a distance of 4 cm from the mean position is $1 / 3$ rd of the maximum kinetic energy. The amplitude of the motion is
A
$2 \sqrt{6} \mathrm{~cm}$
B
$\frac{2}{\sqrt{6}} \mathrm{~cm}$
C
$\sqrt{2} \mathrm{~cm}$
D
$\frac{6}{\sqrt{2}} \mathrm{~cm}$
TS EAMCET Subjects
EXAM MAP