MHT CET 2023 11th May Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2023 11th May Morning Shift

MCQ (Single Correct Answer)

-0

The statement pattern $$\mathrm{p} \rightarrow \sim(\mathrm{p} \wedge \sim \mathrm{q})$$ is equivalent to

$$\mathrm{q}$$

$$(\sim p) \vee q$$

$$(\sim p) \wedge q$$

$$(\sim p) \vee(\sim q)$$

MHT CET 2023 11th May Morning Shift

MCQ (Single Correct Answer)

-0

$$\mathrm{a}$$ and $$\mathrm{b}$$ are the intercepts made by a line on the co-ordinate axes. If $$3 \mathrm{a}=\mathrm{b}$$ and the line passes through $$(1,3)$$, then the equation of the line is

$$x+3 y=10$$

$$3 x+y=6$$

$$x-3 y+8=0$$

$$3 x-2 y+3=0$$

MHT CET 2023 11th May Morning Shift

MCQ (Single Correct Answer)

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Let $$\bar{a}, \bar{b}$$ and $$\bar{c}$$ be three unit vectors such that $$\bar{a} \times(\bar{b} \times \bar{c})=\frac{\sqrt{3}}{2}(\bar{b}+\bar{c})$$. If $$\bar{b}$$ is not parallel to $$\bar{c}$$, then the angle between $$\bar{a}$$ and $$\bar{b}$$ is

$$\frac{5 \pi}{6}$$

$$\frac{2 \pi}{3}$$

$$\frac{\pi}{6}$$

$$\frac{\pi}{3}$$

MHT CET 2023 11th May Morning Shift

MCQ (Single Correct Answer)

-0

The vector equation of the line $$2 x+4=3 y+1=6 z-3$$ is

$$\overline{\mathrm{r}}=\left(2 \hat{\mathrm{i}}+\frac{1}{3} \hat{\mathrm{j}}+\frac{1}{2} \hat{\mathrm{k}}\right)+\lambda(3 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\overline{\mathrm{k}})$$

$$\overline{\mathrm{r}}=\left(-2 \hat{\mathrm{i}}-\frac{1}{3} \hat{\mathrm{j}}+\frac{1}{2} \hat{\mathrm{k}}\right)+\lambda(3 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\hat{\mathrm{k}})$$

$$\overline{\mathrm{r}}=(2 \hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}})+\lambda(3 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\overline{\mathrm{k}})$$

$$\overline{\mathrm{r}}=(-2 \hat{\mathrm{i}}-\hat{\mathrm{j}}+\hat{\mathrm{k}})+\lambda(3 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\hat{\mathrm{k}})$$

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