1
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

Let $$\bar{a}=2 \hat{i}+\hat{j}-2 \hat{k}$$ and $$\bar{b}=\hat{i}+\hat{j}$$. If $$\bar{c}$$ is a vector such that $$\overline{\mathrm{a}} \cdot \overline{\mathrm{c}}=|\overline{\mathrm{c}}|,|\overline{\mathrm{c}}-\overline{\mathrm{a}}|=2 \sqrt{2}$$ and the angle between $$(\bar{a} \times \bar{b})$$ and $$\bar{c}$$ is $$\frac{\pi}{6}$$, then $$|(\bar{a} \times \bar{b}) \times \bar{c}|$$ is

A
$$\frac{3}{2}$$
B
$$\frac{2}{3}$$
C
1
D
$$\frac{3}{4}$$
2
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

$$\int_\limits{-1}^3\left(\cot ^{-1}\left(\frac{x}{x^2+1}\right)+\cot ^{-1}\left(\frac{x^2+1}{x}\right)\right) \mathrm{d} x=$$

A
$$\left(\frac{\pi}{4}\right)$$
B
$$\pi$$
C
$$\left(\frac{\pi}{2}\right)$$
D
$$(2 \pi)$$
3
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$P=\left[\begin{array}{lll}1 & \alpha & 3 \\ 1 & 3 & 3 \\ 2 & 4 & 4\end{array}\right]$$ is the adjoint of a $$3 \times 3$$ matrix $$A$$ and $$|A|=4$$, then value of $$\alpha$$ is

A
4
B
11
C
5
D
0
4
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$\mathrm{f}(x)=\left\{\begin{array}{ll}\frac{\sqrt{1+\mathrm{m} x}-\sqrt{1-\mathrm{m} x}}{x}, & -1 \leq x < 0 \\ \frac{2 x+1}{x-2} & , 0 \leq x \leq 1\end{array}\right.$$ is continuous in the interval $$[-1,1]$$, then $$\mathrm{m}$$ is equal to

A
$$\frac{1}{2}$$
B
$$-\frac{1}{2}$$
C
$$-1$$
D
$$-\frac{1}{4}$$
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