1
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

Let $$\mathrm{f}(x)$$ be positive for all real $$x$$. If $$\mathrm{I}_1=\int_\limits{1-\mathrm{h}}^{\mathrm{h}} x \mathrm{f}(x(1-x)) \mathrm{d} x$$ and $$\mathrm{I}_2=\int_\limits{1-\mathrm{h}}^{\mathrm{h}} \mathrm{f}(x(1-x)) \mathrm{d} x$$, where $$(2 h-1)>0$$, then $$\frac{I_1}{I_2}$$ is

A
2
B
$$\mathrm{h}$$
C
$$\frac{1}{2}$$
D
1
2
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The mirror image of the point $$(1,2,3)$$ in a plane is $$\left(-\frac{7}{3},-\frac{4}{3},-\frac{1}{3}\right)$$. Thus, the point _________ lies on this plane.

A
$$(1,-1,1)$$
B
$$(-1,-1,1)$$
C
$$(1,1,1)$$
D
$$(-1,-1,-1)$$
3
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$\alpha=3 \sin ^{-1} \frac{6}{11}$$ and $$\beta=3 \cos ^{-1}\left(\frac{4}{9}\right)$$, where the inverse trigonometric functions take only the principal values, then the correct option is

A
$$\cos \beta>0$$
B
$$\sin \beta<0$$
C
$$\cos (\alpha+\beta)>0$$
D
$$\cos \alpha<0$$
4
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

$$\text { The value of } \sec ^2\left(\tan ^{-1} 2\right)+\operatorname{cosec}^2\left(\cot ^{-1} 3\right) \text { is }$$

A
4
B
9
C
2
D
15
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