If half of the space between the plates of a parallel plate capacitor is filled with a medium of dielectric constant 4 , the capacitance is $C_1$. If one-third of the space between the plates of the capacitor is filled with the medium of dielectric constant 4 , the capacitance is $C_2$. If in both cases, the dielectric is placed parallel to the plated of the capacitor, then $C_1: C_2=$

The natural frequency of an $L-C$ circuit is 120 kHz . When the capacitor in the circuit is totally filled dielectric material, the natural frequency of the circuit decreases by 20 kHz . Dielectric constant of material is

Three capacitors of capacitances $10 \mu \mathrm{~F}, 5 \mu \mathrm{~F}$ and $20 \mu \mathrm{~F}$ are connected in series with a 14 V DC supply. The charge on $5 \mu \mathrm{~F}$ capacitor is

The circuit shows two capacitor $A$ and $B$ of capacitances $C$ and $2 C$ respectively.

When they are fully charged, the cell is removed and the capacitors are connected with their plates of opposite polarities touching each other. Then

(i) Charge on $A$ is $\frac{4 C E}{9}$

(ii) Charge on $B$ is zero

(iii) Loss of energy in this process is $\left(C E^2 / 3\right)$

The correct statement/s is/are