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TS EAMCET 2023 (Online) 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The electric potential at a place is varying as $V=\frac{1}{2}\left(y^2-4 x\right) \mathrm{V}$. Then, the electric field at $x=1 \mathrm{~m}$ and $y=1 \mathrm{~m}$ is
A
$(2 \hat{i}+\hat{\mathrm{j}}) \mathrm{Vm}^{-1}$
B
$(-2 \hat{\mathbf{i}}+\hat{\mathrm{j}}) \mathrm{Vm}^{-1}$
C
$(2 \hat{\mathbf{i}}-\hat{\mathbf{j}}) \mathrm{Vm}^{-1}$
D
$(-2 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}) V \mathrm{~m}^{-1}$
TS EAMCET Subjects
EXAM MAP