1
TS EAMCET 2020 (Online) 14th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a uniformly charged sphere of total charge $Q$ and radius $R$, the electric field $E$ is plotted as function of distance from the centre of the sphere. The graph which would correspond to the above description will be

A

TS EAMCET 2020 (Online) 14th September Evening Shift Physics - Electrostatics Question 1 English Option 1

B

TS EAMCET 2020 (Online) 14th September Evening Shift Physics - Electrostatics Question 1 English Option 2

C

TS EAMCET 2020 (Online) 14th September Evening Shift Physics - Electrostatics Question 1 English Option 3

D

TS EAMCET 2020 (Online) 14th September Evening Shift Physics - Electrostatics Question 1 English Option 4

2
TS EAMCET 2020 (Online) 14th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Electric charges $+q$ and $-q$ are placed at points $A$ and $B$ respectively which are at a distance of $2 L$ apart. If $C$ is the midpoint between $A$ and $B$, then the work done in moving a charge $+Q$ along the semi-circle $C R D$ is

TS EAMCET 2020 (Online) 14th September Evening Shift Physics - Electrostatics Question 2 English

A

$\frac{q Q}{2 \pi \varepsilon_0 L}$

B

$\frac{q Q}{6 \pi \varepsilon_0 L}$

C

$-\frac{q Q}{6 \pi \varepsilon_0 L}$

D

$\frac{q Q}{4 \pi \varepsilon_0 L}$

3
TS EAMCET 2020 (Online) 14th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

Choose the incorrect statement.

A

Gauss's law applies to a closed surface of any shape.

B

According to Gauss's law, if a closed surface encloses no charge, electric field must vanish everywhere on the surface.

C

Gauss's law can be derived from Coulomb's law.

D

According to Gauss's law, the net number of lines crossing any closed surface in an outward direction is proportional to the net charge on surface.

4
TS EAMCET 2020 (Online) 14th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

In a regular polygon of 10 sides, each corner is at a distance $R$ from the centre. Identical charges are placed at 9 corners. At the centre, the magnitude of electric field is $E$ and the potential is $V$. The ratio $\frac{V}{E}$ is

A

$10 R$

B

$\frac{9}{R}$

C

$\frac{9}{10} R$

D

$9 R$

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