The sum of bond order of $\mathrm{O}_2^{+}, \mathrm{O}_2^{-}, \mathrm{O}_2$ and $\mathrm{O}_2^{2+}$ is equal to

Observe the following statements

Statement-I Hybridisation is not same in both $\mathrm{SF}_6$ and $\mathrm{BrF}_5$.

Statement-II $\mathrm{BrF}_5$ is square pyramidal while $\mathrm{SF}_6$ is octahedral in shape.

The correct answer is

Observe the following list of molecules. Number of polar and non-polar molecules are respectively

$\mathrm{NH}_3, \mathrm{BF}_3, \mathrm{NF}_3, \mathrm{H}_2 \mathrm{~S}_2, \mathrm{CO}_2, \mathrm{CH}_4, \mathrm{CHCl}_3, \mathrm{H}_2 \mathrm{O}$

The molecule ' $X$ ' has see-saw shape with central atom in $s p^3 d$ hybridisation. What is ' $X$ '?