1
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

The solution of $${x^3}{{dy} \over {dx}} + 4{x^2}\tan y = {e^x}\sec y$$ satisfying y (1) = 0, is

A
$$\tan y = (x - 2){e^x}\log x$$
B
$$\sin y = {e^x}(x - 1){x^{ - 4}}$$
C
$$\tan y = (x - 1){e^x}{x^{ - 3}}$$
D
$$\sin y = {e^x}(x - 1){x^3}$$
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