Indefinite Integration · Mathematics · BITSAT

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MCQ (Single Correct Answer)

BITSAT 2022
The value of $$\int {{1 \over {{{[{{(x - 1)}^3}{{(x + 2)}^5}]}^{{1 \over 4}}}}}dx} $$, is
BITSAT 2022
Let $$f(x) = \int {{{{x^2}dx} \over {(1 + {x^2})(1 + \sqrt {1 + {x^2}} )}}} $$ and $$f(0) = 0$$, then the value of $$f(1)$$ be
BITSAT 2021
$$\int {{1 \over {1 - 2\sin x}}dx} $$ is equal to
BITSAT 2020
$$\int {{{8{x^{43}} + 13{x^{38}}} \over {{{({x^{13}} + {x^5} + 1)}^4}}}dx} $$ equals to
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