1
BITSAT 2020
MCQ (Single Correct Answer)
+3
-1
The solution of the equation $${{dy} \over {dx}} + {1 \over x}\tan y = {1 \over {{x^2}}}\tan y\sin y$$ is
2
BITSAT 2020
MCQ (Single Correct Answer)
+3
-1
The solution of differential equation $$(x{y^5} + 2y)dx - xdy = 0$$, is
3
BITSAT 2020
MCQ (Single Correct Answer)
+3
-1
A curve passes through (2, 0) and the slope of the tangent at P(x, y) is equal to $${{{{(x + 1)}^2} + y - 3} \over {x + 1}}$$ then the equation of the curve is
Questions Asked from Differential Equations (MCQ (Single Correct Answer))
Number in Brackets after Paper Indicates No. of Questions
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