MCQ (Single Correct Answer)

1
A projectile is projected with velocity of $ 40 \mathrm{~m} / \mathrm{s} $ at an angle $ \theta $ with the horizontal. If $ R $ be the horizontal range covered by the projectile and after $ t $ seconds, its inclination with horizontal becomes zero, then the value of $ \cot \theta $ is [Take, $ g=10 \mathrm{~m} / \mathrm{s}^{2} $ ]
BITSAT 2024
2

A boat crosses a river from part $$A$$ to part $$B$$, which are just on the opposite side. The speed of the water. $$v_\omega$$ and the of boat is $$v_B$$ relative to still water. Assume $$v_B=\sqrt{2} v_\omega$$. What is the time taken by the boat, if it has to cross the river directly on the $$A B$$ line ($$D=$$ width of the river) ?

BITSAT 2023
3

A projectile is projected with the velocity of $$(3\widehat i + 4\widehat j)$$ m/s. The horizontal range of the projectile will be

BITSAT 2022
4

A man walks in a straight line for 5 min with a velocity of 45 m/s. What is the speed with which he has to move in order to comeback to its original position in 1.5 min?

BITSAT 2021
5

A projectile is given an initial velocity of $$(\widehat i + \widehat j)$$ m/s, where, $$\widehat i$$ is along the ground and $$\widehat j$$ is along the vertical. If g = 10 m/s2, then the equation of its trajectory is

BITSAT 2021
6

Based on the provided velocity-time graph for an object’s straight-line movement, determine the total distance covered and the average speed between t = 0 and t = 20 seconds.

BITSAT 2020 Physics - Motion Question 4 English

BITSAT 2020
7

The acceleration of a particle in m/s2 is given by a = (3t2 $$-$$ 2t + 1), where t is in second. If the particle starts with a velocity v = 1 m/s at t = 1s, then velocity of the particle at the end of 4s is

BITSAT 2020
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