Differential Equations · Mathematics · BITSAT

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MCQ (Single Correct Answer)

BITSAT 2023
If $$\left(1+x^2\right) d y+2 x y d x=\cot x d x$$, then the general solution be
BITSAT 2022
$$\left( {{{dy} \over {dx}}} \right)\tan x = y{\sec ^2}x + \sin x$$, find general solution
BITSAT 2021
Solution of $$\left( {{{x + y - 1} \over {x + y - 2}}} \right){{dy} \over {dx}} = \left( {{{x + y + 1} \over {x + y + 2}}} \right)$$, given that y = 1...
BITSAT 2021
The solution of $${x^3}{{dy} \over {dx}} + 4{x^2}\tan y = {e^x}\sec y$$ satisfying y (1) = 0, is
BITSAT 2020
The solution of the equation $${{dy} \over {dx}} + {1 \over x}\tan y = {1 \over {{x^2}}}\tan y\sin y$$ is
BITSAT 2020
The solution of differential equation $$(x{y^5} + 2y)dx - xdy = 0$$, is
BITSAT 2020
A curve passes through (2, 0) and the slope of the tangent at P(x, y) is equal to $${{{{(x + 1)}^2} + y - 3} \over {x + 1}}$$ then the equation of the...
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