1
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
The locus of the point of intersection of the lines $ x=a\left(\frac{1-t^{2}}{1+t^{2}}\right) $ and $ y=\frac{2 a t}{1+t^{2}} $ represent $ (t $ being a parameter)
A
Circle
B
Parabola
C
Ellipse
D
Hyperbola
2
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
The locus of the mid-point of a chord of the circle $ x^{2}+y^{2}=4 $, which subtends a right angle at the origin is
A
$ x+y=2 $
B
$ x^{2}+y^{2}=1 $
C
$ x^{2}+y^{2}=2 $
D
$ x+y=1 $
3
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

If the straight line $$y=m x+c$$, touches the circle $$x^2+y^2=a^2$$ at a point, then $$c^2$$ is

A
$$m^2\left(1-a^2\right)$$
B
$$m^2\left(1+a^2\right)$$
C
$$a^2\left(1-m^2\right)$$
D
$$a^2\left(1+m^2\right)$$
4
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

A normal is drawn at the point $$P$$ to the circle $$x^2+y^2=25$$, which is inclined at $$45^{\circ}$$ with the straight line $$y=6$$. Then, the point lies on the straight line

A
$$y=x$$
B
$$y=-x$$
C
$$y=\sqrt{3} x$$
D
$$\sqrt{3} y=x$$
BITSAT Subjects
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