1
TS EAMCET 2020 (Online) 14th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A block of mass $m$ placed on a rough horizontal plane is pulled by a constant power $P$. The coefficient of friction between the block and the surface is $\mu$. The maximum velocity of the block will be

A

$\frac{\mu P}{m g}$

B

$\frac{\mu m g}{P}$

C

$\mu m g P$

D

$\frac{P}{\mu m g}$

2
TS EAMCET 2020 (Online) 14th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

The graph of potential energy $U(x)$ versus distance $x$ is shown in the following figure. The force $F$ versus distance $x$ graph will be represented by (assume, that the force is conservative)

TS EAMCET 2020 (Online) 14th September Morning Shift Physics - Work, Energy and Power Question 3 English

A

TS EAMCET 2020 (Online) 14th September Morning Shift Physics - Work, Energy and Power Question 3 English Option 1

B

TS EAMCET 2020 (Online) 14th September Morning Shift Physics - Work, Energy and Power Question 3 English Option 2

C

TS EAMCET 2020 (Online) 14th September Morning Shift Physics - Work, Energy and Power Question 3 English Option 3

D

TS EAMCET 2020 (Online) 14th September Morning Shift Physics - Work, Energy and Power Question 3 English Option 4

3
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

The block starts from rest as shown in the figure. Find the work done by force of 10 N and friction in the time 0 to 4 s . [Take, $g=10 \mathrm{~m} / \mathrm{s}^2$ ]

TS EAMCET 2020 (Online) 11th September Evening Shift Physics - Work, Energy and Power Question 5 English

A

$240 \mathrm{~J},-96 \mathrm{~J}$

B

$250 \mathrm{~J}, 96 \mathrm{~J}$

C

$240 \mathrm{~J}, 96 \mathrm{~J}$

D

$250 \mathrm{~J},-96 \mathrm{~J}$

4
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Under action of force, a 2 kg body moves such that its position $x$ as function of time $t$ is given by $x=\alpha t^2 / 2$, where $x$ is in metre, $t$ is in seconds and $\alpha=1 \mathrm{~m} / \mathrm{s}^2$. The work done by the force in the first two seconds is

A

4 J

B

16 J

C

40 J

D

2 J

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