$$ \text { Match the following. } $$
| $$ \text { List-I (Element) } $$ |
$$ \text { List-II }\left(\Delta_{\mathrm{e}g} H\right) \text { (in } \mathrm{kJmol}^{-1} \text { ) } $$ |
||
|---|---|---|---|
| A. | O | I. | -200 |
| B. | F | II. | -349 |
| C. | Cl | III. | -141 |
| D. | S | IV. | -328 |
| V. | +48 | ||
The correct answer is
Observe the following data ( $\Delta_t H_1, \Delta_t H_2$ and $\Delta_{\mathrm{eg}} H$ represent the first, second ionisation enthalpies and electron gain enthalpy respectively)
| $$ \text { Element } $$ |
$$ \Delta_l H_1\left(\mathrm{kJmol}^{-1}\right) $$ |
$$ \Delta_1 H_2\left(\mathrm{kJmol}^{-1}\right) $$ |
$$ \Delta_{\mathrm{eg}} H\left(\mathrm{kJmol}^{-1}\right) $$ |
|---|---|---|---|
| I | 520 | 7300 | -60 |
| II | 490 | 3051 | -48 |
| III | 1681 | 3374 | -328 |
| IV | 2372 | 5251 | +48 |
Using the data identify the most reactive metal.
Atomic numbers of three elements $E_1, E_2$ and $E_3$ of periodic table are $Z_1, 50$ and $Z_2$ respectively. From the position of the elements shown in figure, the values of $\left(Z_2-Z_1\right)$ is

Electron gain enthalpy values $\left(\Delta_{\mathrm{cg}} H\right)$ (in $\mathrm{kJ} \mathrm{mol}^{-1}$ ) of elements $X, Y$ and $Z$ are $-349,-200$ and -295 respectively. $X, Y$ and $Z$ are respectively
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