1
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0
A body projected vertically up with an initial speed of $10 \mathrm{~ms}^{-1}$ reaches the point of projection after sometime with a speed of $8 \mathrm{~ms}^{-1}$. The maximum height reached by the body is (Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
A

5 m

B

3.2 m

C

4.1 m

D

4.5 m

2
TG EAPCET 2025 (Online) 2nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The driver of a bus moving with a velocity of $72 \mathrm{~km} / \mathrm{h}$ observes a boy walking across the road at a distance of 50 m in front of the bus and decelerates the bus at $5 \mathrm{~ms}^{-2}$ by applying brakes and is just able to avoid an accident. The reaction time of the driver is

A

4 s

B

3.5 s

C

0.5 s

D

4.5 s

3
TG EAPCET 2025 (Online) 2nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The initial and final velocities of a body projected vertically from the ground are $20 \mathrm{~ms}^{-1}$ and $18 \mathrm{~ms}^{-1}$ respectively. The maximum height reached by the body is (Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )

A

20 m

B

16.2 m

C

19 m

D

18.1 m

4
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The position $x$ (in metre) of a particle moving along a straight line is given by $x=t^{3}-12 t+3$, where $t$ is time (in second). The acceleration of the particle when its velocity becomes $15 \mathrm{~ms}^{-1}$ is
A
$15 \mathrm{~ms}^{-2}$
B
$24 \mathrm{~ms}^{-2}$
C
$18 \mathrm{~ms}^{-2}$
D
$12 \mathrm{~ms}^{-2}$

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