1
TG EAPCET 2024 (Online) 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
A body is falling freely from the top of a tower of height 125 m . The distance covered by the body during the last second of its motion is $x \%$ of the height of the tower. Then, $x$ is (Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
A
9
B
36
C
25
D
49
2
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The ratio of the displacements of a freely falling body during first, second and third seconds of its motion is

A
$1: 1: 1$
B
$1: 3: 5$
C
$1: 2: 3$
D
$1: 4: 9$
3
TS EAMCET 2023 (Online) 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The relation between time $t$ and distance $x$ of a particle is $t=a x^2+b x$, where $a$ and $b$ are constants. If $v$ is the velocity of the particle, then its acceleration is
A
$-2 a b v^2$
B
$2 b v^3$
C
$-2 a v^3$
D
$2 a v^2$
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