The Henry's law constant $$(\mathrm{K}_{\mathrm{H}})$$ values of three gases $$(\mathrm{A}, \mathrm{B}, \mathrm{C})$$ in water are $$145, 2 \times 10^{-5}$$ and $$35 \mathrm{~kbar}$$ respectively. The solubility of these gases in water follow the order:
Given below are two statements:
Statement I: The boiling point of hydrides of Group 16 elements follow the order $$\mathrm{H}_2 \mathrm{O}>\mathrm{H}_2 \mathrm{Te}>\mathrm{H}_2 \mathrm{Se}>\mathrm{H}_2 \mathrm{S} \text {. }$$
Statement II: On the basis of molecular mass, $$\mathrm{H}_2 \mathrm{O}$$ is expected to have lower boiling point than the other members of the group but due to the presence of extensive $$\mathrm{H}$$-bonding in $$\mathrm{H}_2 \mathrm{O}$$, it has higher boiling point.
In the light of the above statements, choose the correct answer from the options given below:
Intramolecular hydrogen bonding is present in
Given below are two statements:
Statement I : The boiling point of three isomeric pentanes follows the order
n-pentane > isopentane > neopentane
Statement II : When branching increases, the molecule attains a shape of sphere. This results in smaller surface area for contact, due to which the intermolecular forces between the spherical molecules are weak, thereby lowering the boiling point.
In the light of the above statements, choose the most appropriate answer from the options given below: