1
NEET 2019
MCQ (Single Correct Answer)
+4
-1
Change Language
Which is the correct thermal stability order for H2E (E = O, S, Se, Te and Po)?
A
H2Po < H2Te < H2Se < H2S < H2O
B
H2Se < H2Te < H2Po < H2O < H2S
C
H2S < H2O < H2Se < H2Te < H2Po
D
H2O < H2S < H2Se < H2Te < H2Po
2
NEET 2019
MCQ (Single Correct Answer)
+4
-1
Change Language
For a cell involving one electron $$E_{cell}^\Theta $$ = 0.59 V at 298 K, the equilibrium constant for the cell reaction is :

[Given that $${{2.303RT} \over F}$$ = 0.059 V at T = 298 K ]
A
1.0 $$ \times $$ 1030
B
1.0 $$ \times $$ 1010
C
1.0 $$ \times $$ 102
D
1.0 $$ \times $$ 105
3
NEET 2019
MCQ (Single Correct Answer)
+4
-1
Change Language
For an ideal solution, the correct option is :
A
$$\Delta $$mixH = 0 at constant T and P
B
$$\Delta $$mixG = 0 at constant T and P
C
$$\Delta $$mixS = 0 at constant T and P
D
$$\Delta $$mixV $$ \ne $$ 0 at constant T and P
4
NEET 2019
MCQ (Single Correct Answer)
+4
-1
Change Language
For the cell reaction
2Fe3+(aq) + 2I (aq) $$ \to $$ 2Fe2+(aq) + I2(aq)
$${E_{cell}^\Theta }$$ = 0.24 V at 298 K. The standard Gibbs energy ($$\Delta $$rGo) of the cell reaction is :
[Given that Faraday constant F = 96500 C mol–1]
A
46.32 kJ mol–1
B
23.16 kJ mol–1
C
–46.32 kJ mol–1
D
–23.16 kJ mol–1
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