1
GATE CSE 1996
MCQ (Single Correct Answer)
+2
-0.6
A solution to the Dining Philosophers Problem which avoids deadlock is
A
ensure that all philosophers pick up the left fork before the right fork.
B
ensure that all philosophers pick up the right fork before the left fork
C
ensure that one particular philosopher picks up the left fork before the right fork, and that all other philosophers pick up the right fork before the left fork
D
None of the above.
2
GATE CSE 1996
MCQ (Single Correct Answer)
+1
-0.3
A ROM is sued to store the table for multiplication of two $$8$$-bit unsigned integers. The size of ROM required is
A
$$256 \times 16$$
B
$$64\,K \times 8$$
C
$$4\,K \times 16$$
D
$$64\,K \times 16$$
3
GATE CSE 1996
MCQ (Single Correct Answer)
+2
-0.6
A $$1000$$ Kbyte memory is managed using variable partitions but to compaction. It currently has two partitions of sizes $$200$$ Kbytes and $$260$$ Kbytes respectively. The smallest allocation request in Kbytes that could be denied is for
A
$$151$$
B
$$181$$
C
$$231$$
D
$$541$$
4
GATE CSE 1996
Subjective
+5
-0
A demand paged virtual memory system uses $$16$$ bit virtual address, page size of $$256$$ bytes, and has $$1$$ Kbyte of main memory. $$LRU$$ page replacement is implemented using a list, whose current status (page numbers in decimal ) is GATE CSE 1996 Operating Systems - Memory Management Question 22 English
$$\eqalign{ & \,\, \uparrow \cr & LRU\,Page \cr} $$
For each hexa decimal address in the address sequence given below,
$$00FF,$$ $$010D,$$ $$10FF,$$ $$11B0$$
Indicate,
i) The new status of the list
ii) Page faults, if any, and
iii) Page replacements, if any
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
CBSE
Class 12