The order of reactivity of the following compounds towards the esterification with acetic acid is

Reactions that produce $n$-butanol in the following are :

I. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}=\mathrm{CH}_2 \xrightarrow[\text { (ii) } \mathrm{NaOH} / \mathrm{H}_2 \mathrm{O}_2]{\text { (i) } \mathrm{B}_2 \mathrm{H}_6}$

II. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CHO} \xrightarrow[\text { (ii) } \mathrm{H}_2 \mathrm{O}]{\text { (i) } \mathrm{CH}_3 \mathrm{Mgl}}$

III. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CN} \xrightarrow[\substack{\text { (ii) } \mathrm{H}_3 \mathrm{O} \\ \text { (iii) } \mathrm{NaBH}_4}]{\text { (i) } \mathrm{SnCl}_2, \mathrm{HCl}}$

IV. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CO}_2 \mathrm{H} \xrightarrow{\mathrm{B}_2 \mathrm{H}_6}$

$$ \text { Match the following } $$

$$ \begin{array}{llll} \hline & \begin{array}{c} \text { List-I } \\ \text { (Reaction) } \end{array} & & \begin{array}{c} \text { List-II } \\ \text { (Product) } \end{array} \\ \hline \text { A. } & \text { Ketone }+\mathrm{NaBH}_4 & \text { I. } & 1^{\circ} \text { - alcohol } \\ \hline \text { B. } & \text { Ester }+\mathrm{LiAlH}_4 & \text { II. } & 3^{\circ} \text { - alcohol } \\ \hline \text { C. } & R \mathrm{Mg} X+\text { Ketone } & \text { III. } & 2^{\circ} \text { - alcohol } \\ \hline & & \text { IV. } & \text { Alkane } \\ \hline \end{array} $$

$$ \text { The correct match is } $$

$$ \text { The major product formed in the following reactions is } $$