1
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

Let $$\frac{1}{16}, a$$ and $$b$$ be in GP and $$\frac{1}{a}, \frac{1}{b}, 6$$ be in AP, where $$a, b>0$$. Then, $$72(a+b)$$ is equal to

A
12
B
14
C
16
D
18
2
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

If $$a_1, a_2, \ldots, a_n$$ are in HP, then the expression $$a_1 a_2+a_2 a_3+\ldots+a_{n-1} a_n$$ is equal to

A
$$n\left(a_1-a_n\right)$$
B
$$(n-1)\left(a_1-a_n\right)$$
C
$$n a_1 a_n$$
D
$$(n-1) a_1 a_n$$
3
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

Given, a sequence of 4 numbers, first three of which are in GP and the last three are in AP with common difference 6. If first and last term of this sequence are equal, then the last term is

A
4
B
2
C
8
D
16
4
BITSAT 2022
MCQ (Single Correct Answer)
+3
-1

Let a1, a2, ...... a40 be in AP and h1, h2, ..... h10 be in HP. If a1 = h1 = 2 and a10 = h10 = 3, then a4h7 is

A
2
B
3
C
5
D
6
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