1
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

Given, a sequence of 4 numbers, first three of which are in GP and the last three are in AP with common difference 6. If first and last term of this sequence are equal, then the last term is

A
4
B
2
C
8
D
16
2
BITSAT 2022
MCQ (Single Correct Answer)
+3
-1

Let a1, a2, ...... a40 be in AP and h1, h2, ..... h10 be in HP. If a1 = h1 = 2 and a10 = h10 = 3, then a4h7 is

A
2
B
3
C
5
D
6
3
BITSAT 2022
MCQ (Single Correct Answer)
+3
-1

Let a1, a2, a3 .... be a harmonic progression with a1 = 5 and a20 = 25. The least positive integer n for which an < 0, is

A
22
B
23
C
24
D
25
4
BITSAT 2022
MCQ (Single Correct Answer)
+3
-1

In a sequence of 21 terms, the first 11 terms are in AP with common difference 2 and the last 11 terms are in GP with common ratio 2. If the middle term of AP be equal to the middle term of the GP, then the middle term of the entire sequence is

A
$$-\frac{10}{31}$$
B
$$\frac{10}{31}$$
C
$$\frac{32}{31}$$
D
$$-\frac{31}{32}$$
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