1
TS EAMCET 2022 (Online) 19th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

A bullet is fired at time $t=0$ with velocity $20 \mathrm{~m} / \mathrm{s}$ and at an initial angle of $30^{\circ}$ with the horizontal. The angle between the displacement vector and the horizontal after time 0.1 s is (assume $g=10 \mathrm{~m} / \mathrm{s}^2$ ).

A

$\frac{38}{20 \sqrt{3}}$

B

$\frac{19}{20 \sqrt{3}}$

C

$\frac{19}{20}$

D

$\frac{19 \sqrt{3}}{20}$

2
TS EAMCET 2022 (Online) 19th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

A man walking along a straight line with a velocity 6 $\mathrm{km} / \mathrm{h}$ encounters rain falling vertically down with a velocity $6 \sqrt{3} \mathrm{~km} / \mathrm{h}$. At what angle the man should hold his umbrella, so that he can protect himself from rain

A

$30^{\circ}$ with respect to ground

B

$30^{\circ}$ with respect to vertical

C

$45^{\circ}$ with respect to ground

D

$60^{\circ}$ with respect to vertical

3
TS EAMCET 2022 (Online) 18th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

A projectile is given an initial velocity of $(3 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}) \mathrm{m} / \mathrm{s}$ where $\hat{\mathbf{i}}$ is along the ground and $\hat{\mathbf{j}}$ is along the vertical. Assuming $g=10 \mathrm{~m} / \mathrm{s}^2$, if the equation of its trajectory can be written as $\frac{1}{9}\left[\beta x+\gamma x^2\right]$. Then the value of $\gamma$ is

A

-8

B

-5

C

-6

D

-12

4
TS EAMCET 2022 (Online) 18th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

A small object slides down with initial velocity equal to zero from the top of a smooth hill of height $H$. The other end of the hill is horizontal and is at height $H / 2$ as shown in the figure. The horizontal distance covered by the object from the end of the hill to the ground is

TS EAMCET 2022 (Online) 18th July Evening Shift Physics - Motion in a Plane Question 21 English

A

2 H

B

H

C

$\frac{H}{2}$

D

$\frac{3 H}{2}$

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