In one molal solution that contains 0.5 mole of a solute, there is
RMgX + CO2 $$\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{ether}^{dry}} $$ Y $$\buildrel {{H_3}{O^ + }} \over \longrightarrow $$ RCOOH
What is Y in the above reaction?
Given below are half cell reactions:
$$MnO_4^ - + 8{H^ + } + 5{e^ - } \to M{n^{2 + }} + 4{H_2}O$$,
$$E_{M{n^{2 + }}/MnO_4^ - }^o = - 1.510\,V$$
$${1 \over 2}{O_2} + 2{H^ + } + 2{e^ - } \to {H_2}O$$
$$E_{{O_2}/{H_2}O}^o = + 1.223\,V$$
Will the permanganate ion, $$MnO_4^ - $$ liberate O2 from water in the presence of an acid?
What mass of 95% pure CaCO3 will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction?
CaCO3(s) + 2HCl(aq) $$\to$$ CaCl2(aq) + Co2(g) + 2H2O(l)
[Calculate upto second place of decimal point]