1
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Change Language
A potentiometer wire has length 4 m and resistance 8 $$\Omega $$. The resistance that must be connected in series with the wire and an accumulator of e.m.f. 2 V, so as to get a potential gradient 1 mV per cm on the wire is
A
44 $$\Omega $$
B
48 $$\Omega $$
C
32 $$\Omega $$
D
40 $$\Omega $$
2
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Change Language
An electron moving in a circular orbit of radius r makes n rotations per second. The magnetic field produced at the centre has magnitude
A
$${{{\mu _0}{n^2}e} \over r}$$
B
$${{{\mu _0}ne} \over {2r}}$$
C
$${{{\mu _0}ne} \over {2\pi r}}$$
D
Zero
3
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Change Language
A conducting square frame of side 'a' and a long straight wire carrying current $$I$$ are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity 'V'. The emf induced in the frame will be proportional to

AIPMT 2015 Cancelled Paper Physics - Moving Charges and Magnetism Question 64 English
A
$${1 \over {{{\left( {2x + a} \right)}^2}}}$$
B
$${1 \over {\left( {2x - a} \right)\left( {2x + a} \right)}}$$
C
$${1 \over {{x^2}}}$$
D
$${1 \over {{{\left( {2x - a} \right)}^2}}}$$
4
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Change Language
A wire carrying current $$I$$ has the shape shown in adjoining figure.

AIPMT 2015 Cancelled Paper Physics - Moving Charges and Magnetism Question 65 English
Linear parts of the wire are very long and parallel to X-axis while semicircular protion of radius R is lying in Y-Z plane. Magtnetic field at pont $$O$$ is
A
$$\overrightarrow B = - {{{\mu _0}I} \over {4\pi R}}\left( {\pi \widehat i + 2\widehat k} \right)$$
B
$$\overrightarrow B = {{{\mu _0}I} \over {4\pi R}}\left( {\pi \widehat i - 2\widehat k} \right)$$
C
$$\overrightarrow B = {{{\mu _0}I} \over {4\pi R}}\left( {\pi \widehat i + 2\widehat k} \right)$$
D
$$\overrightarrow B = - {{{\mu _0}I} \over {4\pi R}}\left( {\pi \widehat i - 2\widehat k} \right)$$
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