1
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is
A
$${{W\left( {d - x} \right)} \over x}$$
B
$${{W\left( {d - x} \right)} \over d}$$
C
$${{Wx} \over d}$$
D
$${{Wd} \over x}$$
2
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
A mass m moves in a circle on a smooth horizontal plane with velocity v0 at a radius R0. The mass is attached to a string which passes through a smooth hole in the plane as shown. the tension in the string is increased gradually and finally m moves in a circle of radius $${{{R_0}} \over 2}$$.

The final value of the kinetic energy is
AIPMT 2015 Cancelled Paper Physics - Rotational Motion Question 67 English
A
2mv$$_0^2$$
B
$${1 \over 2}$$mv$$_0^2$$
C
mv$$_0^2$$
D
$${1 \over 4}$$mv$$_0^2$$
3
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Three identical spherical shells, each of mass m and radius r are placed as shown in figure. Consider an axis XX' which is touching to two shells and passing through diameter of third shell. Moment of inertia of the system consisting of these three spherical shells about XX' axis is

AIPMT 2015 Cancelled Paper Physics - Rotational Motion Question 66 English
A
$${{16} \over 5}m{r^2}$$
B
4mr2
C
$${{11} \over 5}m{r^2}$$
D
3mr2
4
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Kepler's third law states that square of period of revoluation (T) of a planet around the sun, is proportional to third power of average distance r between sun and planet i.e. T2 = Kr3 here K is constant. If the masses of sun and planet are M and m respectively then as per Newton's law of gravitation force of attraction between them is F = $${{GMm} \over {{r^2}}}$$, here G is gravitational constant. The relation between G and K is described as
A
K = G
B
K = $${1 \over G}$$
C
GK = 4$$\pi $$2
D
GMK = 4$$\pi $$2
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