1
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Change Language
A wire carrying current $$I$$ has the shape shown in adjoining figure.

AIPMT 2015 Cancelled Paper Physics - Moving Charges and Magnetism Question 65 English
Linear parts of the wire are very long and parallel to X-axis while semicircular protion of radius R is lying in Y-Z plane. Magtnetic field at pont $$O$$ is
A
$$\overrightarrow B = - {{{\mu _0}I} \over {4\pi R}}\left( {\pi \widehat i + 2\widehat k} \right)$$
B
$$\overrightarrow B = {{{\mu _0}I} \over {4\pi R}}\left( {\pi \widehat i - 2\widehat k} \right)$$
C
$$\overrightarrow B = {{{\mu _0}I} \over {4\pi R}}\left( {\pi \widehat i + 2\widehat k} \right)$$
D
$$\overrightarrow B = - {{{\mu _0}I} \over {4\pi R}}\left( {\pi \widehat i - 2\widehat k} \right)$$
2
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Change Language
A resistance 'R' draws power 'P' when connected to an AC source. If an inductance is now placed in series with the resistance, such that the impedance of the circuit becomes 'Z'. the power drawn will be
A
$$P\left( {{R \over Z}} \right)$$
B
P
C
$$P{\left( {{R \over Z}} \right)^2}$$
D
$$P\sqrt {{R \over Z}} $$
3
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Change Language
A particle is executing SHM along a straight line. Its velocities at distances x1 and x2 from the mean position are V1 and V2 respectively. Its time period is
A
$$2\pi \sqrt {{{V_1^2 + V_2^2} \over {x_1^2 + x_2^2}}} $$
B
$$2\pi \sqrt {{{V_1^2 - V_2^2} \over {x_1^2 - x_2^2}}} $$
C
$$2\pi \sqrt {{{x_1^2 + x_2^2} \over {V_1^2 + V_2^2}}} $$
D
$$2\pi \sqrt {{{x_2^2 - x_1^2} \over {V_1^2 - V_2^2}}} $$
4
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Change Language
For a parallel beam of monochromatic light of wavelength '$$\lambda $$' , diffraction is produced by a single slit whose width 'a' is of the order of the wavelength of the light. If 'D' is the distance of the screen from the slit, the wifth of the central maxima will be
A
$${{Da} \over \lambda }$$
B
$${{2Da} \over \lambda }$$
C
$${{2D\lambda } \over a}$$
D
$${{D\lambda } \over a}$$
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