1
AIPMT 2012 Prelims
MCQ (Single Correct Answer)
+4
-1
Change Language
The motion of a particle along a straight line is described by equation x = 8 + 12t $$-$$ t3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is
A
24 m s$$-$$2
B
zero
C
6 m s$$-$$2
D
12 m s$$-$$2
2
AIPMT 2012 Prelims
MCQ (Single Correct Answer)
+4
-1
Change Language
Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and B is moving with velocity v along x-axis. After collision B has a velocity $${v \over 2}$$ in a direction perpendicular to the original direction. The mass A moves after collision in the direction :
A
same as that of B
B
opposite to that of B
C
$$\theta $$ = tan$$-$$1 $$\left( {{1 \over 2}} \right)$$ to the x-axis
D
$$\theta $$ = tan$$-$$1$$\left( { - {1 \over 2}} \right)$$ to the x-axis
3
AIPMT 2012 Prelims
MCQ (Single Correct Answer)
+4
-1
Change Language
The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is
A
$$\theta $$ = tan$$-$$1$$\left( {{1 \over 4}} \right)$$
B
$$\theta $$ = tan$$-$$1(4)
C
$$\theta $$ = tan$$-$$1(2)
D
$$\theta $$ = 45o
4
AIPMT 2012 Prelims
MCQ (Single Correct Answer)
+4
-1
Change Language
The potential energy of a particle in a force field is $$U = {A \over {{r^2}}} - {B \over r}$$ where A and B are positive constants and r is the distance of particle from the centre of the field. For stable equilibrium, the distance of the particle is
A
$${B \over {2A}}$$
B
$${{2A} \over B}$$
C
$${A \over B}$$
D
$${B \over A}$$