1
MHT CET 2023 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Water flows through a horizontal pipe at a speed '$$\mathrm{V}$$'. Internal diameter of the pipe is '$$\mathrm{d}$$'. If the water is coming out at a speed '$$V_1$$' then the diameter of the nozzle is

A
$$\mathrm{d \sqrt{\frac{V_1}{V}}}$$
B
$$\mathrm{d \sqrt{\frac{V}{V_1}}}$$
C
$$\frac{\mathrm{dV}}{\mathrm{V}_1}$$
D
$$\frac{\mathrm{V}_1}{\mathrm{dV}}$$
2
MHT CET 2023 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment the separation between the slits is doubled without changing other setting of the experiment to obtain same fringe width, the distance 'D' of the screen from slit should be made

A
$$\frac{\mathrm{D}}{2}$$
B
$$\frac{\mathrm{D}}{\sqrt{2}}$$
C
$$2 \mathrm{D}$$
D
$$4 \mathrm{D}$$
3
MHT CET 2023 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A body is released from the top of a tower '$$\mathrm{H}$$' metre high. It takes $$t$$ second to reach the ground. The height of the body $$\frac{t}{2}$$ second after release is

A
$$\frac{\mathrm{H}}{2}$$ metre from ground
B
$$\frac{\mathrm{H}}{4}$$ metre from ground
C
$$3 \frac{\mathrm{H}}{4}$$ metre from ground
D
$$\frac{\mathrm{H}}{6}$$ metre from ground
4
MHT CET 2023 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

There is a second's pendulum on the surface of earth. It is taken to the surface of planet whose mass and radius are twice that of earth. The period of oscillation of second's pendulum on the planet will be

A
$$2 \sqrt{2} \mathrm{~s}$$
B
$$2 \mathrm{~s}$$
C
$$\frac{1}{\sqrt{2}} \mathrm{~s}$$
D
$$\frac{1}{2} \mathrm{~s}$$
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