1
BITSAT 2020
MCQ (Single Correct Answer)
+3
-1
The root of the equation $$2(1 + i){x^2} - 4(2 - i)x - 5 - 3i = 0$$, where $$i = \sqrt { - 1} $$, which has greater modulus, is
2
BITSAT 2020
MCQ (Single Correct Answer)
+3
-1
If $$z = r{e^{i\theta }}$$, then arg(eiz) is
Questions Asked from Complex Numbers (MCQ (Single Correct Answer))
Number in Brackets after Paper Indicates No. of Questions
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