1
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

If $$f(x) = \left\{ {\matrix{ {a{x^2} + 1,} & {x \le 1} \cr {{x^2} + ax + b,} & {x > 1} \cr } } \right.$$ is differentiable at x = 1, then

A
a = 1, b = 1
B
a = 1, b = 0
C
a = 2, b = 0
D
a = 2, b = 1
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