If $$\frac{d y}{d x}+\frac{y}{x}=x^2$$, then $$2 y(2)-y(1)=$$

The solution of the differential equation $$\frac{d y}{d x}=(x+y)^2$$ is

If $$y(x)$$ is the solution of differential equation $$x \log x \frac{d y}{d x}+y=2 x \log x, y(e)$$ is equal to

The sum of the degree and order of the differential equation $$\left(l+y_1^2\right)^{2 / 3}=y_2$$ is