Definite Integration · Mathematics · KCET

$\int_{-\pi}^\pi\left(1-x^2\right) \sin x \cdot \cos ^2 x d x$ is

$\int\limits_1^5(|x-3|+|1-x|) d x=$

$$\int\limits_2^8 \frac{5^{\sqrt{10-x}}}{5^{\sqrt{x}}+5^{\sqrt{10-x}}} d x \text { is equals to :}$$

$$\int_{-2}^0\left(x^3+3 x^2+3 x+3+(x+1) \cos (x+1)\right) d x$$ is equals to

$$\int\limits_0^\pi \frac{x \tan x}{\sec x \cdot \operatorname{cosec} x} d x$$ is equals to

If $$[x]$$ is the greatest integer function not greater than $$x$$, then $$\int_\limits0^8[x] d x$$ is equal to

$$\int_0^{\pi / 2} \sqrt{\sin \theta} \cos ^3 \theta d \theta$$ is equal to

$$\int_0^1 \frac{x e^x}{(2+x)^3} d x$$ is equal to

Evaluate $$\int_\limits2^3 x^2 d x$$ as the limit of a sum

$$\int_0^{\pi / 2} \frac{\cos x \sin x}{1+\sin x} d x$$ is equal to

If $$I_n=\int_0^{\frac{\pi}{4}} \tan ^n x d x$$, where $$n$$ is positive integer, then $$I_{10}+I_8$$ is equal to

The value of $$\int_0^{4042} \frac{\sqrt{x} d x}{\sqrt{x}+\sqrt{4042-x}}$$ is equal to

The value of $$\int_{-1 / 2}^{1 / 2} \cos ^{-1} x d x$$ is

Find the value of $$\int_0^1 \frac{\log (1+x)}{1+x^2} d x$$ is

The value of $$\int_{-\pi / 2}^{\pi / 2} \frac{\cos x}{1+e^x} d x$$ is

$$\int_\limits{-3}^3 \cot ^{-1} x d x=$$

$$\int_\limits0^2\left[x^2\right] d x=$$

$$\int_\limits0^1 \sqrt{\frac{1+x}{1-x}} d x=$$

$$ \int\limits_{-\pi / 2}^{\pi / 2} \frac{d x}{e^{\sin x}+1} $$

$$ \int\limits_0^{\pi / 2} \frac{1}{a^2 \cdot \sin ^2 x+b^2 \cdot \cos ^2 x} d x $$