Chemical Equilibrium · Chemistry · KCET

At $$500 \mathrm{~K}$$, for a reversible reaction $$A_2(g)+B_2(g) \rightleftharpoons 2 A B(g)$$ in a closed container, $$K_C=2 \times 10^{-5}$$. In the presence of catalyst, the equilibrium is attaining 10 times faster. The equilibrium constant $$K_C$$ in the presence of catalyst at the same temperature is

1 mole of $$\mathrm{HI}$$ is heated in a closed container of capacity of $$2 \mathrm{~L}$$. At equilibrium half a mole of $$\mathrm{HI}$$ is dissociated. The equilibrium constant of the reaction is

For the reaction,

$$A(g)+B(g) \rightleftharpoons C(g)+D(g) ; \Delta H=Q \mathrm{~kJ}$$

The equilibrium constant cannot be disturbed by