Compounds Containing Nitrogen · Chemistry · KCET

Which of the following reagents are suitable to differentiate Aniline and N-methylaniline chemical

$$ \text { Which of the following reaction/s does not yield an amine? } $$

$$ \text { Match the compounds given in List - I with the items given in List - II. } $$

Biologically active adrenaline and ephedrine used to increase blood pressure contain

In the reaction, Aniline $\xrightarrow[\text { Dil. } \mathrm{HCl}]{\mathrm{NaNO}_2} P \xrightarrow[\text { NaOH }]{\text { Phenol }} Q$

In the reaction,

$${C_6}{H_5}CN\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{(ii)\,{H_3}{O^ + }}^{(i)\,SnC{l_2} + HCl}} X\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{}^{conc.\,KOH}} Y + Z$$

Formation of $$X, Y$$ and $$Z$$ are known by

Aniline does not undergo

In the reaction,

P, Q and R respectively are

Identify the products $$A$$ and $$B$$ in the reactions :

$$\begin{aligned} & R-X+\mathrm{AgCN} \longrightarrow A+\mathrm{Ag} X \\ & R-X+\mathrm{KCN} \longrightarrow B+\mathrm{KX} \end{aligned}$$

In carbylamine test for primary amines the resulting foul smelling product is

A secondary amine is

$$\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{Cl} \xrightarrow{\text { Alc. } \mathrm{NH}_3} A \xrightarrow{2 \mathrm{CH}_3 \mathrm{Cl}} B.$$ The product $$B$$ is

The method by which aniline cannot be prepared is

A hydrocarbon $$A\left(\mathrm{C}_4 \mathrm{H}_8\right)$$ on reaction with $$\mathrm{HCl}$$ gives a compound $$\mathrm{B}\left(\mathrm{C}_4 \mathrm{H}_9 \mathrm{Cl}\right)$$ which on reaction with $$1 \mathrm{~mol}$$ of $$\mathrm{NH}_3$$ gives compound $$\mathrm{C}\left(\mathrm{C}_4 \mathrm{H}_{10} \mathrm{N}\right)$$. On reacting with $$\mathrm{NaNO}_2$$ and $$\mathrm{HCl}$$ followed by treatment with water, compound $$C$$ yields an optically active compound $$D$$. The compound $$D$$ is

The compound A (major product) is

The final product for the reaction is

Hinsberg's reagent is

Which of the following is least soluble in water at $$298 \mathrm{~K}$$ ?

If aniline is treated with $$1: 1$$ mixture of conc. $$\mathrm{HNO}_3$$ and conc. $$\mathrm{H}_2 \mathrm{SO}_4$$, p-nitroaniline and $$m$$-nitroaniline are formed nearly in equal amounts. This is due to