The modulus of the complex number $$\frac{(1+i)^2(1+3 i)}{(2-6 i)(2-2 i)}$$ is

If $$3 x+i(4 x-y)=6-i$$ where $$x$$ and $$y$$ are real numbers, then the values of $$x$$ and $$y$$ are respectively,

If $$\left(\frac{1+i}{1-i}\right)^x=1$$, then

If $$z=x+i y$$, then the equation $$|z+1|=|z-1|$$ represents