If a curve passes through the point $$(1,1)$$ and at any point $$(x, y)$$ on the curve, the product of the slope of its tangent and $$x$$ coordinate of the point is equal to the $$y$$ coordinate of the point, then the curve also passes through the point

The degree of the differential equation $$1+\left(\frac{d y}{d x}\right)^2+\left(\frac{d^2 y}{d x^2}\right)^2=\sqrt[3]{\frac{d^2 y}{d x^2}+1}$$ is

If $$\frac{d y}{d x}+\frac{y}{x}=x^2$$, then $$2 y(2)-y(1)=$$

The solution of the differential equation $$\frac{d y}{d x}=(x+y)^2$$ is